Physics problem help ASAP?

1200 rev/min x 1min/60s = 20 rev/s

circumference = 2πR = 2π5.6 = 35.19 cm, one rev

20 rev/s x 35.19 cm/rev = 703.7 cm/s = 7.037 m/s

acceleration (outward) at rim is a = rω² = V²/r

V is the tangental velocity in m/s

r is radius of circle in meters

ω is angular velocity in radians/sec

a is in m/s²

ω = 20 rev/s x 2π rad/rev = 125.7 rad/s

a = rω² = 0.056•125.7² = 884 m/s²

As the disk rotates one time an object on the outer row of data will move a distance that is equal to the circumference of a circle.

C = 2 * π * 0.056 = π * 0.112

The circumference of the circle is approximately 0.35 meters. The object moves 1200 times this distance in 60 seconds.

v = 1200 * π * 0.112 * π ÷ 60 = 2.24 * π

The velocity is approximately 7.04 m/s. Since the outer row of data is moving around a circle at a constant speed, it has centripetal acceleration.

a = v^2 ÷ r = 5.0176 * π^2 ÷ 0.056 = 89.6 * π^2

The centripetal acceleration is approximately 884 m/s^2. I hope this is helpful for you.

(a) 1200 rev/min = 20 rev/sec.

(20 rev/s)*(2*pi*0.056 m/rev)

= maybe 7 m/s, use calculator.

(b) a = v^2/r, where r = 0.056m and v comes from part (a) above.

V = ω*r = 1200rev/60s * 2πrad/rev *0.056 = 1.12m/s <<<<< a.

a = V²/r = 1.12²/0.056 = 22.4m/s² <<<<< b.