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Calculus Derivatives help?

I'm having trouble finding the first derivative of these two problems, any help would be much appreciated.

a. 5x^3-3x^5-3tan^6(pi/12)^2

b. (x^2*sqrt(x^3+1))/(x-2)

3 Answers

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  • Favorite Answer

    What in the world is 3 * tan^6(pi/12)^2? Is it 3 * tan((pi/12)^2)^6? Either way, without a variable present, you could just call it a constant C

    5x^3 - 3x^5 - C

    That's easy enough to derive

    15x^2 - 15x^4

    x^2 * sqrt(x^3 + 1) / (x - 2)

    u = x^2 * sqrt(x^3 + 1)

    u^2 = x^4 * (x^3 + 1)

    u^2 = x^7 + x^4

    2u * du = 7x^6 * dx + 4x^3 * dx

    du/dx = (7x^6 + 4x^3) / (2u)

    u' = x^3 * (7x^3 + 4) / (2 * x^2 * sqrt(x^3 + 1))

    u' = x * (7x^3 + 4) / (2 * sqrt(x^3 + 1))

    v = x - 2

    v' = 1

    d(u/v) = (v * u' - u * v') / v^2

    ((x - 2) * x * (7x^3 + 4) / (2 * sqrt(x^3 + 1)) - x^2 * sqrt(x^3 + 1) * 1) / (x - 2)^2 =>

    (1/sqrt(x^3 + 1)) * ((x - 2) * x * (7x^3 + 4) * sqrt(x^3 + 1) - x^2 * (x^3 + 1)) / (x - 2)^2 =>

    (x * (x - 2) * (7x^3 + 4) * sqrt(x^3 + 1) / 2 - x^2 * (x^3 + 1)) / ((x - 2)^2 * sqrt(x^3 + 1)) =>

    (x * (x - 2) * (7x^3 + 4) * sqrt(x^3 + 1) - 2 * x^2 * (x^3 + 1)) / (2 * (x - 2)^2 * sqrt(x^3 + 1))

  • 2 years ago

    What's wrong with a derivative calculator?

  • Anonymous
    2 years ago

    That question is too hard for people on here you need to go ask a university professor

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