Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

I need help with my physics hw. I already attempted it, but I don't understand what I'm meant to do.?

If 10% of an 80-kg rock climber's total energy expenditure goes into the gravitational energy change when climbing a 70-m vertical slope, what is the climber's average metabolic rate (in Watts) during the climb if it takes her 11 min to complete the climb?

5 Answers

Relevance
  • oubaas
    Lv 7
    4 months ago

    power P = 70*80*9.806/(0.1*60*11) = 830 watt (quite a number, being more than 1HP) ) 

  • 4 months ago

    There are FOUR things being tested.  1 Do you recognize that in SI you must use seconds for time.?  2.  Do you know that power = energy / time?  3.  Do you recognize that gravitational energy = mgh. 4. IF 10 % goes into gravity how do you find 100% when you know 10%?

    OK so metabolic energy =mgh *100/10

    Power = metabolic energy / time = mgh * 100/10 / (11*60) = 80*9.8*70 *10/(11*60) ~=830W  Which is a very realistic figure.

  • Ash
    Lv 7
    4 months ago

    Gravitational energy change = mgh = (80 kg)(9.8 m/s²)(70 m) = 54880 J

    If gravitational energy change of 54880 J is 10%, then total energy expended will be...

    Total energy = (100%/10%)*54880 J = 548800 J

    Average metabolic rate = Total energy/time in sec = (548800 J)/[(11min * 60)s] ≈ 832 W

  • 4 months ago

    energy to climb 70 m, E = mgh = 80•9.8•70 = 54880 J

    total energy expended would be 10 times that or 548800 J

    power in watts = energy in joules / time in seconds

    11 min = 660 s

    P = 548800 J / 660 s = 832 J/s or 832 watts

  • How do you think about the answers? You can sign in to vote the answer.
  • 4 months ago

    What is the energy needed to move an 80 kg mass upwards by 70 m in the Earth's gravitational field.?

    The question says that that amount of energy is only 10% of the climber's energy over an 11 minute period, so the total energy in 11 minutes is 10X as much.   The metabolic rate is the average energy expenditure per unit time.

Still have questions? Get your answers by asking now.