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Trigonometry question ?
Suppose csc(90-θ)=3/2. without using inverse trig functions, find the value of sin θ, sec θ, and cot θ
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- ?Lv 73 months ago
csc(90 - θ) = 3/2. sin θ,
sin(θ) = sin(90 - sin^(-1)(2/3)), sin(θ) = -sin(90 + sin^(-1)(2/3))
sec(θ) = sec(90 - sin^(-1)(2/3)), sec(θ) = -sec(90 + sin^(-1)(2/3))
and
cot(θ) = cot(90 - sin^(-1)(2/3)), cot(θ) = cot(90 + sin^(-1)(2/3)
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