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Trigonometry question?
suppose sin θ=0.568. without using inverse trig functions, find sin(90-θ), cos (90-θ) and tan (90-θ)
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- ted sLv 73 months ago
assuming degree measure sin (90 - Θ) = cos Θ = √(1 - 0.568²) , cos (90 - Θ) = sin Θ {given} , and tan(90 - Θ) is the ratio of those previous found numbers
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