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geometry question?
triangle abc is isosceles with angle A as the vertex angle. find the perimeter of abc if ca=2x+14, cb =x+8 and ab=4x
4 Answers
- ?Lv 73 months ago
Triangle ABC is isosceles with angle A as the vertex angle.
CA = 2x + 14, CB = x + 8 and AB = 4x
CA = AB, x = 7
The perimeter of ABC: 71
- DavidLv 73 months ago
If the two equal sides of the isosceles triangle are 4x = 2x+14 then x = 7 and so its perimeter is (4*7)+((2*7)+14)+(7+8) = 71 units of measurement
- billrussell42Lv 73 months ago
isosceles means two sides are equal. You list 3 sides, but which are which? my guess is ca and ab
2x+14 = 4x
2x = 14
x = 7
ca = 2x+14 = 28
cb = x+8 = 15
ab = 4x 28
perimeter = sum = 71
- jacob sLv 73 months ago
AB= 4x BC= x + 8
AB= AC
4x = 2x + 14
2x= 14
x = 7
P= 4x + x + 8 + 2x + 14
P = 4*7 + 7 + 8 + 2 *7 + 14
P= 28 + 15 + 14 +14
P= 71