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 In a family with 5 children, what is the probability that a) there is at least one girl? b) there are exactly 2 girls?

1 Answer

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  • 2 weeks ago

    a)

    p(boy) = p(girl) = 1/2p(at least one girl) =1 - p(all boys) =1 - (1/2)^5 =

    1 - 1/32 =

    31/32

    b)

    p(two girls) =

    5C2 * (1/2)^2 *(1 - 1/2)^3 =

    5!/(2!(5 -2)!) * 1/4 *  * 1/8 =

    10 * 1/4 * 1/8 =

    10/32 = 5/16

    Alternatively,

    p(two girls) =

    # of combinations with 2 girls / # of all possible combinations =

    5C2/2^5 =

    (5!/(2!(5 - 2)!)) / 32 =

    10 / 32 = 5/16

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