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Angle question?

The take-off path of a 747 jet forms a 40° angle with the runway. At this angle, how far will the plane fly before reaching its cruising altitude of

10 000 metres?

2 Answers

Relevance
  • 1 day ago

    xsin(40) = 10000m

    xcos(40) = d

    take 1st and solve for x

    xsin(40) = 10000m

    x = 10000m/sin(40)

    d = xcos(40) = 10000mcos(40)/sin(40) = 10000mcot(40) = 11916m

  • Ian H
    Lv 7
    1 day ago

    10,000/d = tan(40°) solve for d

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