A few algebra questions? Please help me out?

1. Which answer describes the restrictions for the variables?
x - 4/x + 1 (it's a fraction)

All the equal signs have a dash through them.
A) x = -4
B) x = 1
C) x = 4
D) x = -1
Is it a?

2. Which expression is in simplified form for the given expression in states the correct variable restriction?
u^2 - 2u / u^2 - 4 (It's a fraction)

All the equal signs have a dash through them.
A) u/u+2, u = -2
B) u-2/u+2, u = -2, and u = 2
C) 1/u+2, u = -2
D) u/u+2, u = -2, and u = 2

3. Multiply. Assume that no denominator equal zero.
9t^2/s multiplied by 5st^2/36

A) 5t^4/4
B) 5t^3/4
C) 5t^3/4s^2
D) 5t^4/9

DC2015-12-17T11:21:09Z

1) Consider that it is a fraction, and that a denominator with a zero is undefined, so there is no answer, thus restricts the x value that would result in a zero. The denominator is x + 1. So the domain will be restricted when:

x + 1 = 0

Subtract 1 from both sides:

x = -1, So when x is negative one the denominator is zero, so no it is not A.

2) First we can simplify the expression by factoring both numerator and denominator. The numerator can factor out a u. The denominator is the difference of two squares so its' factors will appear in the form (a + b)(a - b).

(u^2 - 2u) / (u^2 - 4)

u(u - 2) / (u + 2)(u - 2)

We can see the numerator and the denominator have a common factor and thus will cancel each other. So the simplified form looks like:

u/(u + 2)

Next to consider restrictions again we seek to know the denominator is zero. If either (u + 2) or (u - 2) equals zero then the denominator will be zero so the function would be restricted at that point. So when does u + 2 = 0? When u = -2. And when does u - 2 = 0? When u = 2.

3) Well, The multiplication is simple enough: then just cancel/reduce like factors.

Multiplied we get ((45)(t^4)(s))/((36)(s))

One 's' in each the numerator and denominator so they cancel each other.
45/36 can be reduced to 5/4 so the final product is ((5)(t^4))/(4)