Ninety-one passengers rode in a train from City A to City B. Tickets for regular coach seats cost $119. Tickets for sleeper cars seats cost $294. The receipts for the trip totaled $19,404. How many passengers purchased each type of ticket?
Number of coach tickets purchased?
Number of sleeper car tickets purchased?
Please
iceman
let r & s be the number of regular & sleeper tickets:
r + s = 91 => multiply by -119
119 r + 294 s = 19404
-119 r - 119 s = - 10829
119 r + 294 s = 19404 => add the two equations, r's cancel, solve for s:
175 s = 8575
s = 49 => plug into one of the equations, solve for r:
r = 91 - 49 = 42
thus: 42 passengers purchased Regular coach tickets while 49 slept comfortably in sleeper cars.
I hope this helps.
?
119C+294(91-C) = 19,404
-175C = -7350
Coach passengers = 42
Sleeper = 49
Anonymous
119x+294y=19,404
x+y=91
There are your 2 equations, plug one in and solve for x and y.
y=91-x
119x+ 294(91-x)=19404
119x+26754-294x=19404
-175x+26754=19404
-175x=-7350
x=42
42+y=91
y=49
So regualr coach seats purchased 42
sleepers purchased 49
SirAsksAlot
35000