math question?

let r & s be the number of regular & sleeper tickets:

r + s = 91 => multiply by -119

119 r + 294 s = 19404

-119 r - 119 s = - 10829

119 r + 294 s = 19404 => add the two equations, r's cancel, solve for s:

175 s = 8575

s = 49 => plug into one of the equations, solve for r:

r = 91 - 49 = 42

thus: 42 passengers purchased Regular coach tickets while 49 slept comfortably in sleeper cars.

I hope this helps.

119C+294(91-C) = 19,404

-175C = -7350

Coach passengers = 42

Sleeper = 49

119x+294y=19,404

x+y=91

There are your 2 equations, plug one in and solve for x and y.

y=91-x

119x+ 294(91-x)=19404

119x+26754-294x=19404

-175x+26754=19404

-175x=-7350

x=42

42+y=91

y=49

So regualr coach seats purchased 42

sleepers purchased 49

35000