Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

Puggy
Lv 7
Puggy asked in Science & MathematicsMathematics · 1 decade ago

Is there a name for a function with the property f(xy) = f(x)f(y)?

Suppose that for a particular function,

f(xy) = f(x)f(y)

Is there a name for functions which have this property? I'm thinking multiplicative but that can't be it. I thought of this when the sigma function in number theory had this property.

10 Answers

Relevance
  • 1 decade ago
    Favorite Answer

    If the domain is the integers, then the function is a totally multiplicative function.

    Interesting features:

    f(1) = f (1 * 1) = f(1) * f(1), so f(1) = 0 or f(1) = 1

    If f(1) = 0, then f(x) = f(1 * x) = f(1) * f(x) = 0 * f(x) = 0, so the function is identically zero.

    If f(1) = 1 and the domain is real numbers:

    If x != 0, then

    f(x) * f(1/x) = f(x * 1/x) = f(1) = 1, so f(x) != 0 for x != 0

    1 = f(1) = f(x * 1/x) = f(x) * f(1/x) for all x, so f(1/x) = 1/f(x) for x != 0

    this means that f(a/b) = f(a)/f(b) for b != 0

  • 5 years ago

    I think they should do anything that is better to do collectively that isn't better served by private industry. National Parks is an example of s resource that should be shared by everyone. Somethings would be very unequal if left to the marketplace- education for instance. Access to utilities is another example. If it weren't for the government many poor or rural areas wouldn't have electricity or phones. They also need to be a check on the greed of capitalism and make sure products are safe, businesses are run fairly and employees are treated fairly. While I am far from communist, i am sure i picture a larger role for government than the tea-baggers. So go ahead, thumbs down me. I'm a big girl and can take it.

  • 1 decade ago

    Indeed, a function with this property is called a completely multiplicative function. Often, it is used in integer functions i.e. functions with the (sub)set of integers as the domain. A simple one is the function f defined as f(even integer) = 0 and f(odd integer) = 1. Then f(xy) = f(x)f(y).

  • Anonymous
    1 decade ago

    "Multiplicative" is indeed one term for such a function.

    "Operation preserving" is another (perhaps more widely used) term, or we can say that the function "preserves multiplication" if the specific operation it preserves is considered important.

    In general, "f preserves multiplication" is probably the best answer I can give to your question, I think.

    Group and ring homomorphisms do have this property also, but they have to satisfy other things as well (the function's domain and codomain must be groups under multiplication), so calling such a function a "homomorphism" is not necessarily correct.

  • How do you think about the answers? You can sign in to vote the answer.
  • 1 decade ago

    Not a function type, but a term for being able to partition a function like that. "Separation of Variables" Check wiki article on that.

    Addendum: I cede to the other explanations given below, since the subject is about number and group theory.

  • 1 decade ago

    Scythian's comment is good. If you have a partial differential equation under certain conditions you get what's called 'separable' functions.

    Shows up in electrostatics, steady state heat flow...

    also, in statistics for a joint density function, it's a necessary condition for independence.

  • raz
    Lv 5
    1 decade ago

    In abstract algebra, we call functions of this type homomorphisms.

  • 1 decade ago

    yes, it is a homomorphism of groups with the multiplication operation on the reals. .

  • 1 decade ago

    You're right; a link is below.

  • Anonymous
    1 decade ago

    It looks like the DISTRIBUTIVE LAW.

    Guido

Still have questions? Get your answers by asking now.