math question???

let the price of the inferior one be x

then the price of the high quality tea = x + 2

The cost of inferior = 6x

The cost of the high quality one = 3(x+2)

the total cost = 6x + 3(x+2) = 24

therefore 9x + 6 = 24

so 9x = 18

x = 2 per Kg

So the answer is the first one $2 per Kg

$2

6x=inferior

3(x+2)=high quality

6x + 3(x+2)=24

6x + 3x + 6=24

9x = 18

x=2

6(2) + 3(4)=24

$2 per kg=inferior

let x be the cost of inferior quantity tea

let y be the cost of high quantity tea

6x + 3y = 24

y = 2 + x

6x + 3(2 + x) = 24

6x + 6 + 3x = 24

9x = 18

x = 2

$2.00 per kg

the total price of the mixture was $24.00 the total mixture is 9 kg.

we know that the good tea is 3 kg at $2.00 per kg or totaling $6.00

the bad tea part is $24 - $6 = $18.00

The price of the bad tea is $19.00.

The price per kg of the bad tea is $18.00/ 6 kg or $3.00 p[er kg

take 3kg multiply it bye $2 and get $6

subtract $6 from $24 and get $18

divide 6kg by $18 and get $3

so the answer is $3 per kg.

6x+3(x+2) = 24

6x + 3x + 6 = 24

9x = 18

or x = 2

$2.00/ kg

x=Cost of 6kg tea

y=Cost of 3kg tea

6x+2(3x)=24

12x=24

x=2

$2 per kilogram

the answer is 3$ per kg

$5 per kg. i hope that's the right answer