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Religiously speaking, how do you solve ax2 + bx + c = 0 ?

28 Answers

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  • 1 decade ago
    Favorite Answer

    Set x=.0000001 and just wait a few hundred million years - eventually x will evolve into the correct answer!

  • Anonymous
    1 decade ago

    ax2 = 1

    bx = 1

    c = 1

    0 = 1

    ax2 + bx + c = 1 + 1 + 1 = 1

    Source(s): the trinity
  • Anonymous
    1 decade ago

    Ooh! Ohh! I just did this in Math!!!

    ax^2+bx+c=0 [Let us make a=1, b=5, c=4)

    x^2+5x+4=0

    (x+4)(x+1)=0

    x+4=0 or x+1=0

    x=-4 or x=-1

    {-4, -1}

  • Anonymous
    1 decade ago

    Use the quadratic formula. A real nerd knows how to solve this very easily, this is intermediate algebra and your IT83 can be a great help.

    This is the quadratic formula:

    X = -b+-√ b+- 4 A C / 2b

    BTW, stop being such a poser, you're not a nerd, you're a loser. Even a baby knows how to do this

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  • 1 decade ago

    The same way you would solve it non religiously speaking, for the question is not religious in nature.

    Sort of like how does a Christian drive a car? The same way as a nonChristian

  • 1 decade ago

    i have no clue what you mean by religiously speaking, but you factor that when there are numbers there.

    and to factor, you need to see "ok what factors of c add up to B?"

    for example, if it was

    "x^2+2x +1=0 "

    you can see that "1" has the factors of 1X1.

    and 1+1=2.

    and you put that into parenthese, like this.

    so you write that as (x+1)(x+1)

  • Anonymous
    1 decade ago

    Believe.

    EDIT:

    That the roots will fall out the sky and you won't need the quadratic formal and oh now don't even speak of the vertex. And F.U.C lK FOIL all the way to Judus.

    And you're gong to hell for trying to prove it with proofs, say the distribution property 3 times and you are going to hell for 9 years.

  • Anonymous
    1 decade ago

    ax2(b)x2+0=c

    c-bx(a)2+ (0)2+bx(2x/3ab) x 3b + ac/2+ bx

    so c = 6.9892987234987

  • 1 decade ago

    The Father + The Son + The Holy Ghost = NOTHING. Simply because I don't believe they exist.

  • 1 decade ago

    Clearly the trinomial is linked to the biblical trinity.

    So a = God

    b = Jesus

    c = Holy Ghost

    0 = don't exist

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