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MrGuy
Lv 4
MrGuy asked in Science & MathematicsEngineering · 1 decade ago

Using a transistor to switch a circuit on... how?

I have two sperate circuits I need to connect. Both have their own power source and I need to keep it that way. I have two leads that i need to switch power on where a SPST switch is located on the other circuit.

Simply, I have circuit A which needs to be turned on by circuit B, while keeping the power sources seperate.

Circuit B is a VOX switch that applies 4.5v to a remote lead. I need to take that 4.5v and use it to just complete a circuit on Circuit A without applying voltage.

Can I do this with a transistor? I have not been able to. Maybe I have the wrong transistor for this purpose?

I was thinking, use the 4.5v to switch the transistor which would complete the circuit for the switch on Circuit A. But it doesn't work when connected.

To make it very simple, two leads from one circuit need to complete a switch on another circuit without transferring the voltage... I'm just not thinking clearly of why it isnt working.

http://img114.imageshack.us/img114/677/s...

Thats the circuit and the circuit I need to make for it using a relay.

I have relay 275-232 from radioshack. Its a 5v reed relay. But I only have 4.5v switching voltage, which wont turn the relay on. The relay is good, it works with 5.5v applied. But I cant get the 5v to the leads, i only have 4.5v there.

Let me know if you need the values for the circuit components, i didnt put them on.

Update 2:

Its a toggle switch on the upper schematic. It just changes the polarity of the leads going out. The leads out have 4.5v. The top schematic is circuit B. The switch on the lower schematic is circuit A.

Update 3:

The circuit from that schematic works, when the mic receives input (sound) the LEADS OUT go from 0v to 4.5v and then a time delay +/- 6sec (if no sound) and the leads go back to 0v. Problem is I cant get the 4.5v to switch the relay, or a transistor. I looked over the website you provided, its really nice, but as you can tell my electrical expertise isnt the best. I can read schematics, draw them, and make the circuit, but I cant make them. So with a 12v mic relay, Im not really sure how to apply that to a 6v relay to make use out of it.

Update 5:

The VOX circuit is fine, but it doesnt use the op-amp, instead its using CMOS logic. So thats why the circuitry is slightly different.

3 Answers

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  • 1 decade ago
    Favorite Answer

    From the looks of it, you don't have the driver transistor connected properly. It isn't getting any power.

    All you need is to use either a common-base or common-emitter to drive the relay. Also, don't forget to put a back-EMF diode on the coil, or it will damage the transistor.

    Link below looks like a circuit for exactly what you want to do: close a relay based on voice input. At the very least take a look at how the transistor connects to the coil.

    "more" stuff... why bother with the SPDT? If you put the relay in the same case as the other stuff then you have a pair of dry contacts to control the other piece.

    Also, I found an even better VOX circuit (second link). It uses a single-ended supply op-amp and 4.5V (see pp. 18).

  • 5 years ago

    If an opto-isolator is already too large (4-DIP) and too costly ($1.20 per piece), then any other idea will be so, too. You can do this without opto-coupler or relay or pulse transformer, but then at least one potential of both power supplies need to be connected to each other, usually 0 Volt. If I knew more about your "trigger circuit" and what your "transistor relay circuit" has to perform, then I might be able to give a more precise answer.

  • 1 decade ago

    sorry, still having problems understanding this. I see what looks like a DPDT relay in the upper schematic (is that A or B?), but where is the coil for that relay? or is it a toggle switch?

    Where is the 4.5 volts coming from? is that the "leads in" on the schematic? Is the relay in the lower part (B?) part of the relay in the top part?

    please label the schematic re your written description. Part A/B, the 4.5 volts, etc.

    .

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