Jim threw a ball with an initial velosity of V(0) at an angle of alfa above horizon.?

The ball hits the ground in 6 seconds 200 meters away.

Horizontal component of the velocity = 200 / 6 = 33.33 m/s = V(0) cos alpha.

Vetical component of the initial velocity = V(0) sin alpha.

Vetical component of the final velocity at max ht = V1 = 0 m/s

time to reach max ht = 6/2 = 3 sec.

v = u +at

0 = V(0) sin alpha - 9.81 x 3

V(0) sin alpha = 29.43 m/s

we have V(0) cos alpha.= 33.33 m/s

(V(0) sin alpha )^2 + (V(0) cos alpha)^2 = (V(0))^2 = 1977.01

V(0) = 44.46 m/s

1-the initial velosity,V(0) = 44.46 m/s ans

2-the angle alfa in respect to horizon

V(0) sin alpha = 29.43

sin alpha = 29.43 / 44.46 = 0.662

alpha = 41.45* ans

3-maximum height the ball gains

h = ut + 0.5 a t^2

h = 0.5 x 9.81 x9 = 44.145 m ans