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Need help factoring this polynomial completely?

This is the problem: x^5y^3 – 9x^4y^2 + 20x^3y

This is the work I have so far: = xy(x^4y^2 - 9x^3y + 20x^2)

x^5y^3 – 9x^4y^2 + 20x^3y

= xy(x^4y^2 – 9x^3y + 20x^2)

= xy[x^2(x^2 – 9x^2y) – 20x(x – y)

After this stage I'm confused and not even sure if I have done the work correctly so far or not. So if anyone could help me out with this particular problem, it would be greatly appreciated. Thank you.

Update:

Thank you everyone for your help with this particular problem. Was giving me a great deal of trouble.

3 Answers

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  • Anonymous
    1 decade ago
    Favorite Answer

    The problem is you didn't completely factor at the beginning. You should have factored an x^3y, not xy.

    Heres the work:

    x^3y( x^2y^2 - 9xy + 20)

    You would then factor ( x^2y^2 - 9xy + 20), which is

    (xy - 4)(xy -5)

    so the final answer is

    x^3y(xy - 4)(xy -5)

  • ?
    Lv 5
    1 decade ago

    yes this problem can be a bit confusing. here is how i solved it:

    x^5y^3 - 9x^4y^2 + 20X^3y

    factor out GCF: x^3y(x^2y^2 - 9xy + 20)

    now, this looks like it should be hard to solve, but figure that xy=a

    factor the inside: (a^2 - 9a + 20) = (a-4)(a-5)

    replace a with xy: x^3y ( xy - 4 ) ( xy - 5 )

  • 1 decade ago

    From the original polynomial, you need to factor out as much as possible (x^3y):

    x^3y(x^2y^2 - 9xy + 20)

    From there I factored out the latter part using the foil method:

    x^3y(xy-5)(xy-4)

    Hope this helps!

    Source(s): many math courses
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