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Physics impulse question?
A snowmobile has a mass of 250kg. A constant force is exerted on it for 60.0s. The snowmobiles initial velocity is 6.00m/s and its final velocity is 28.0m/s.
(a) What linear impulse does the snowmobile experience?
(b) What is the magnitude of the force exerted on it?
I have an idea of where to start with (a) maybe using p=mv formula I'm a little confused about how to complete the problem
formulas to use..
p=mv
F(average) = delta P / delta t
2 Answers
- jr010xLv 41 decade agoFavorite Answer
F=m*(delta v)
F=m*(v1-v2/t)
F=250*(28-6/60)
F=91.7 kg*m/s
F=ma
F=250*22
F=5500N
- aldiLv 45 years ago
you % contraptions on the plenty. i'm going to assume this is µg. yet certainly the contraptions cancel out, so as long as they're consistant, it quite is okay. replace in momentum is 1µg x 5e7 + 1µg x 0.9 x 5e7 ?P = 1µg x 5e7(a million+0.9) = 50(a million.9) gm/s imparted to the gold, it quite is ?P = 50(a million.9) = 197µg x V V = 482000 m/s .