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6/(x-8)=3/(x+4), tell what values of x cannot possibly be the solution to this equation.?
ive been doing this math problem for an hour i cant figure out how to do this, please help me :(
2 Answers
- 1 decade ago
There are places where there is no answer, and these are where you have to divide by 0.
In this equation, one would be forced to divide by 0 if x-8 = 0, hence x=8 cannot be a solution,
We have the same problem if x+4 = 0, or x=-4. SO we know that there cannot be a solution if x=-4 or x=8.
Dividing by 0 makes the result infinity.
It's easy - when you know how!!
Source(s): |BSc Maths& Physics. - PolyhymnioLv 71 decade ago
8 and –4 are not in the domain, so they cannot possibly be solutions. Better answer: any value that is not –16
