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Cumulative proportions?
EG.
μ=60, σ=14, x=76
z=x-μ/ σ
=76-60/14
=1.14
I rounded off z=1.14 to the nearest z (1.15)
And found the cumulative proportion of z by looking at a random number table, and the value I found in the random number table was 0.8749.
BUT!!! the 'Solutions' stated that the value was 0.87493, which I'm assuming was figured out by hand. Does anyone know how this cumulative proportion was calculated (if it's possible to calculate cumulative proportion by hand)?
1 Answer
- 1 decade agoFavorite Answer
No, you cannot figure it out by hand.
You could use a different standard normal distribution
table sometimes called a z table
{ table IS NOT A RANDOM NUMBER TABLE}
or you could use Microsoft Excel
where you use
=normdist(1.15,0,1,1)
The format of Excel's normdist function is
=normdist(z,µ,σ,1)
of course z is the observed z
With z tables, µ is always 0 and σ is always 1
and the second 1 is to indicate that it is the actual
Cumulative proportion, not simply the ordinate of
the normal distribution{height of density function}
You will allways need that 1 so
use
=normdist(z,0,1,1)
You cannot do this by hand because the formula for
the normal distribution is EXTREMELY unwieldy, you need
computers or calculators(or tables). By hand, one would
use some long numerical methods.