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Finding standard error without σ or n?
A veterinary medical association conducted a survey of veterinary clinics to estimate the proportion that do not treat large animals. The survey was mailed to a random sample of 120 veterinary clinics throughout the country and of these, 88 responded that they do not treat large animals.
The standard error of the proportion 'p' of clinics that do not treat large animals is:
p=120/88 ????
1 Answer
- ?Lv 610 years agoFavorite Answer
For a binomial distribution:
p = x/n proportion of the number of "yes" in n yes/no questions = 88/120 = 0.733
SEp = sqrt [ p(1 - p) / n ] = sqrt [ (0.733 - 0.266)/120] = 0.062
Note: p = 120/88 should set off alarm bells because p cannot be greater than 1 !!
Source(s): http://stattrek.com/Lesson2/Binomial.aspx?Tutorial... http://stattrek.com/AP-Statistics-4/Standard-Error...
