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A few questions regarding electric circuits (calculations)?
Could you provide working out too please? Thanks :D
Q1. Find the current in the 20Ω and 5Ω resistors in the following circuit:
http://i28.lulzimg.com/22c6123200.jpg
Q2. In the circuit below, the reading on the ammeter is 3.2 A.
http://i28.lulzimg.com/77e1d039ac.jpg
Determine:
a) the reading on the voltmeter
b) the potential difference across the 40Ω resistor
c) the current in the 40Ω resistor
Q3. http://i28.lulzimg.com/7d19d5dcbc.jpg
For the circuit above:
a) Determine the total resistance.
b) Find the reading on the ammeter.
c) Draw a voltmeter in the correct place to measure the potential difference across the 0.3 resistor (you can just describe it)
d) Draw an ammeter in the correct place to measure the current in the 0.3 resistor (you can, again, describe the location instead)
e) Determine the readings on the meters mentioned in parts (c) and (d) above.
Thanks in advance!
2 Answers
- 10 years agoFavorite Answer
Q1 answer:
R(total) = 50 + (5 || 20) = 50 + 1/ (1/5 + 1/20) = 50 + 1/ (5/20) = 54 ohms
I (total) = V(battery) / R(total) = 12 / 54 = 2 / 9 Amp
i1 = current in 5 ohm i2 = current in 20 ohm
we have : i1 + i2 = 2/9 and i1 / i2 = 20 / 5 = 4
=> i1 = 8 / 45 amp and i2 = 2 / 45 amp
i1 ~ 0.178 amp and i2 ~ 0.044 amp
Q2 answer:
the exact value of the total current can be calculated as 3.182 amp.
if we consider the I(total)=3.2
we have V(voltmeter) = 3.2 * 10 ohm = 32 volts
=> V (40 ohm) = 50 - 32 = 18 volts
=> I (40 ohm) = 18 / 40 = 0.45 amp
with the more exact value of I (total) ~= 3.182
we have V(voltmeter) = 31.82 volts
=> V (40 ohm) = 50 - 31.82 = 18.18 volts
=> I (40 ohm) = 18.18 / 40 = 0.4545 amp
Q3 answer:
R(total) = 100 + (0.3 || 0.5) = 100 + ( 3 / 16 ) = 100.1875
I (ammeter) = 20 / 100.1875 = 0.19963 amp
c) just connect the voltmeter terminals to each end of the 0.3 resistor
the plus terminal to the top end (in diagram) and the minus terminal to the bottom end.
d) put the ammeter in series with the 0.3 resistor, i.e. draw it on the same wire as the 0.3
resistor
e) V = 20 - 100 * 0.19963 = 0.037 volt
I = 0.037 / 0.3 ~= 0.125 amp
- chronesLv 44 years ago
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