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Please help! 3 ^ (x/2+1)=12.2?

How can I solve for x

3 Answers

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  • 9 years ago
    Favorite Answer

    Knowledge of logarithm is needed to solve this equation.

    3^(x/2+1) = 12.2

    Add lg at both sides,

    lg 3^(x/2+1) = lg 12.2

    (x/2+1) lg 3 = lg 12.2

    (x/2+1) = lg 12.2/lg 3

    (x/2+1) = 2.2769

    x/3 = 2.2769

    x = 2.2769*3

    = 6.8307

  • 9 years ago

    3^((x/2) + 1) = 12.2

    (x/2) + 1 = log (base 3) of 12.2

    x/2 = (log (base 3) of 12.2) - 1

    x = 2*((log (base 3) of 12.2) - 1)

    x =~ 2.55381

    Or did you mean:

    3^(x/(2+1)) = 12.2

    3^(x/3) = 12.2

    x/3 = log (base 3) of 12.2

    x = 3*(log (base 3) of 12.2)

    x =~ 6.83

  • 9 years ago

    let C = 12.2

    then with some rearranging you get

    x = 2*(ln(C)/ln(3)-1)

    x = 2.28

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