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5(x+3)+4x-5=4-2x? solve equation and check solution?
9 Answers
- LuisLv 69 years agoFavorite Answer
Dear Cap America,
5(x+3)+4x-5=4-2x
Multiply 5 by each term inside the parentheses.
5x+15+4x-5=-2x+4
Since 5x and 4x are like terms, add 4x to 5x to get 9x.
9x+15-5=-2x+4
Subtract 5 from 15 to get 10.
9x+10=-2x+4
Since -2x contains the variable to solve for, move it to the left-hand side of the equation by adding 2x to both sides.
9x+10+2x=4
Since 9x and 2x are like terms, add 2x to 9x to get 11x.
11x+10=4
Since 10 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 10 from both sides.
11x=-10+4
Add 4 to -10 to get -6.
11x=-6
Divide each term in the equation by 11.
(11x)/(11)=-(6)/(11)
Simplify the left-hand side of the equation by canceling the common factors.
x=-(6)/(11)
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Check...
5((-(6)/(11))+3)+4(-(6)/(11))-5=4-2(-(6)/(11))
Remove the parentheses around the expression -(6)/(11).
5(-(6)/(11)+3)+4(-(6)/(11))-5=4-2(-(6)/(11))
To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is 11. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions.
5(3*(11)/(11)-(6)/(11))+4(-(6)/(11))-5=4-2(-(6)/(11))
Complete the multiplication to produce a denominator of 11 in each expression.
5((33)/(11)-(6)/(11))+4(-(6)/(11))-5=4-2(-(6)/(11))
Combine the numerators of all fractions that have common denominators.
5((33-6)/(11))+4(-(6)/(11))-5=4-2(-(6)/(11))
Subtract 6 from 33 to get 27.
5((27)/(11))+4(-(6)/(11))-5=4-2(-(6)/(11))
Multiply 5 by each term inside the parentheses.
(135)/(11)+4(-(6)/(11))-5=4-2(-(6)/(11))
Multiply 4 by each term inside the parentheses.
(135)/(11)-(24)/(11)-5=4-2(-(6)/(11))
Combine the numerators of all fractions that have common denominators.
(135-24)/(11)-5=4-2(-(6)/(11))
Subtract 24 from 135 to get 111.
(111)/(11)-5=4-2(-(6)/(11))
To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is 11. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions.
-5*(11)/(11)+(111)/(11)=4-2(-(6)/(11))
Complete the multiplication to produce a denominator of 11 in each expression.
-(55)/(11)+(111)/(11)=4-2(-(6)/(11))
Combine the numerators of all fractions that have common denominators.
(-55+111)/(11)=4-2(-(6)/(11))
Add 111 to -55 to get 56.
(56)/(11)=4-2(-(6)/(11))
Multiply -2 by each term inside the parentheses.
(56)/(11)=4+(12)/(11)
To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is 11. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions.
(56)/(11)=4*(11)/(11)+(12)/(11)
Complete the multiplication to produce a denominator of 11 in each expression.
(56)/(11)=(44)/(11)+(12)/(11)
Combine the numerators of all fractions that have common denominators.
(56)/(11)=(44+12)/(11)
Add 12 to 44 to get 56.
(56)/(11)=(56)/(11)
Since (56)/(11)=(56)/(11), the equation will always be true.
Always True
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Source(s): Precalculus Solved! - Anonymous9 years ago
5(x+3)+4x-5=4-2x
distribute 5 to x and 3
5x+15+4x-5=4-2x
combine like terms
9x+10=4-2x
add 2x to both sides
11x+10=4
subtract 10 from both sides
11x=-6
divide both sides by 11
x=-6/11
to check this plug in -6/11 into the original equation and see if it works
- MICHAEL KLv 79 years ago
5(x + 3) + 4x - 5 = 4 - 2x
5x + 15 + 4x - 5 = 4 - 2x
9x + 10 = 4 - 2x
11x = - 6
x = - 6/11.
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- SunLv 79 years ago
5(x+3)+4x-5=4-2x,
5x+15+4x-5=4-2x,
9x+10=4-2x,
9x-(-2x)+10=4,
11x+10=4,
11x=4-10,
11x=-6,
x=-6/11.
Answer: -6/11.
- Anonymous9 years ago
x= -11/6. Plug that in for x and both sides of the equation should be the exact same value. Hope it helps.
:)
- 9 years ago
I got 1 divided by 11 so thats what i would suggest. So it would be unsolvable.