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How to determine the Exponential function?
Determine the exponential function whose graph contains the following points:
(-1,3/5) and (2,75)
So I know you need to substitute, which I've done. And I'm at this point:
3/5 = (75a)^(-1/2)
Where I'm stuck is that I don't know how to distribute the exponent -1/2 over 75a. If someone could tell me how that be great!
1 Answer
- TravelerLv 68 years agoFavorite Answer
Generally, x^y is equal to e^(y(ln(x)).
In your example (75a) is x and (-1/2) is y, so:
3/5 = e^(-1/2)(ln(75a))
I'm not sure how far you want to go with this, since your equation is in an odd format, but
continuing:
Take natural log of both sides
ln (3/5) = (-1/2)(ln(75a))
-0.5108 = (-1/2)(ln(75a))
Divide both sides by (-1/2)
-1.02165 = ln(75a)
