Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
5 Answers
- Moise GunenLv 78 years agoFavorite Answer
y^2 = 2x +29
y = x - 3
Substitute y = x - 3 into first equation
(x-3)^2 = 2x +29
x^2 - 8x -20 = 0
(x - 10)(x + 2) = 0
x = 10 then y = 7
x = -2 then y = -5
(10, 7)
(-2, -5)
- 8 years ago
The second Equation gives you the value of y.
Substitute it in the first equation and you'll get the answer.
(x - 3)^2 = 2x + 29
x^2 + 9 - 6x = 2x + 29
x^2 - 8x - 20 = 0
Now factorise .
x^2 - 10x + 2x -20 = 0
x( x - 10) + 2( x - 10) = 0
x + 2 = 0 & x - 10 = 0
x = 10 & x = -2
- JasubhaiLv 68 years ago
put value of y from 2 in to 1
(x-3)^=2x+29
x^2-6x+9-2x-29=0
x^2-8x-20=0
(x-10)(x+2)=0
x=10,x=-2 x=10 y=7 x=-2 y=-5
- ComoLv 78 years ago
x^2 - 6x + 9 = 2x + 29
x^2 - 8x - 20 = 0
(x - 10)(x + 2) = 0
x = 10 , x = - 2
y = 7 , y = - 5
- How do you think about the answers? You can sign in to vote the answer.
- 8 years ago
yes, that is one way to start the problem and probably the best/most obvious
Source(s): various lessons in high school
