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equazionii aiutoo 10 pnt al primo :)?
27/20+ {(1+x):2-[(2x+4):3-(9/10-(4x+3):6)-(5x-1):4]}=1-(1-x):2
(5x-1):4]}=1-(1-x):2
1 Answer
- ?Lv 78 years agoFavorite Answer
27/20 + graffa (1-x)/2 - [(2x+4)/3 - (9/10 - (4x+3)/6) - (5x-1)/4] graffa chiusa = 1 - (1-x)/2
27/20 + graffa (1-x)/2 - [(2x+4)/3 - (54 - 40x - 30 - 75 x + 15)/60] graffa chiusa = 1 + (x-1)/2
27/20 + graffa (1-x)/2 - (2x+4)/3 - (- 115x + 29)/60 graffa chiusa = (2+x-1)/2
27/20 + graffa (1-x)/2 - (2x+4)/3 + (115x - 29)/60 graffa chiusa = (x+1)/2
27/20 + graffa [30 (1-x) - 20(2x+4) + 115x - 29]/60 graffa chiusa = (x+1)/2
27/20 + graffa [30 - 30 x - 40 x - 80 + 115x - 29]/60 graffa chiusa = (x+1)/2
27/20 + graffa (45x -79)/60 graffa chiusa - (x+1)/2 = 0
81/60 + 45/60 x - 79/60 - 30/60 x - 30/60 = 0
45x - 30x = - 81 + 79 - 30
15 x = - 32
x = - 32/15
