Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Help with differential calculus?
What is differentiation of log(sinx)cosx? Brackets () means it's log's base.
d(log(sinx)cosx)/dx = ??
2 Answers
- GlippLv 78 years agoFavorite Answer
y = log(sinx)cosx = ln cos x / ln sin x
y ln sin x = ln cos x
y' ln sin x + y cos x / sin x = -sin x / cos x
y' ln sin x + (cos x / sin x)ln cos x / ln sin x = -sin x / cos x
y' ln sin x = -(cos x / sin x)ln cos x / ln sin x - sin x / cos x
y' ln sin x = -cot x log[sin x] cos x - tan x
y' = -(cot x log[sin x] cos x + tan x) / ln sin x
- MelvynLv 78 years ago
y = log(sinx) cos x
(sinx) ^y = cos x
y log sin x = log cos x
y = log cos x / log sin x
dy/dx = ((log sin x )(-sinx )/(cos x) - (log cos x) (cos x /sin x))/ (log sin x ) ^2
now you can simplify
