Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Help with Dynamics FE Examination Problem (Forces and Motion)?
A 550 Kg mass initially at rest is acted upon by a force of 50e^t N. What are the acceleration , velocity and displacement of the mass at t=4s?
3 Answers
- Anonymous8 years agoFavorite Answer
F-ma gives (*): 50e^t=550d²s/dt²=550dv/dt. Integrating gives
v=(1/11)e^t+C. When t=0, v=0, so C=-1/11→(**) v=(1/11)(e^t-1).
By (*) at t= 4, a=d²s/dt²=(1/11)e^4=4.96m/s².
By (**) v=4.873m/s.
v=ds/dt=(1/11)(e^t-1)→
s=(1/11)e^t-t/11+C'. When t=0, s=0→
C'=-1/11→s=(1/11)e^t-t/11-1/11→
s(4)=4.509m.
- ?Lv 68 years ago
CAREFUL.... F=ma ONLY IF acceleration is constant
otherwise its:
F=m*dv/dt
F*dt=m*dv
intigrate
50*e^t*dt
gives
50*e^t=m*v+C <---forgot +C first time around and its important
v=50/m*e^t+C
V at t=0 needs to be zero, since object starts at rest
V(0)=0=50/m*e^0+C
C=-50/m
v=50/m*(e^t-1)
a=dv/dt
a=50/m*e^t
v=ds/dt
or
ds=v*dt
s=50/m(e^t-t)+C <====once again forgot C the first try
S at t=0 also needs to be zero
s(0)=0=50/m(e^0-0)+C
C=-50/m
s=50/m*(e^t-t-1)
so you have
a=50/m*e^t
v=50/m*(e^t-1)
s=50/m*(e^t-t-1)
a(4)=50/550*e^4
v(4)=50/550*(e^4-1)
s(4)=50/550*(e^4-5)