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Calculus Limits Help Please?
Need to show numerical evidence concerning the existence of this limit:
Limit 50x^2/sinx + 50x^2
X approaches 0
I am not sure how to manipulate the expression here. Thanks in advance
1 Answer
- az_lenderLv 78 years agoFavorite Answer
Maybe you mean 50x^2/(sin(x)+50x^2).
Otherwise the addend doesn't have any effect on the existence of the limit. PLEASE learn basic algebra "order of operations".
Anyway, a fine piece of numerical evidence is provided by just substituting some very small numbers for x. When x = 0.001, the expression has a value
very close to 0.05, and when x = 0.00001, the expression has a value very close to 0.0005.
Since the limit as x->0 of x/sin(x) is 1, it makes sense that the value as x->0 of 50x^2/[sin(x)+50x^2] would be close to 50x, and hence the limit is zero.