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vector calculus question?
The thickness of the frosting at a point on a rectangular piece of brownie is equal to one
twentieth of the square of the horizontal distance from that point to the bottom left corner of
the brownie when seen from above. If the brownie is three inches wide by two inches across,
what is the average thickness of frosting on the brownie?
1 Answer
- 8 years agoFavorite Answer
f(x,y) = (x² + y²)/20
2 3
(1/A)∫ ∫ f(x,y) dx dy = ⅙∫∫(x² + y²) dx dy /20
0 0
= (1/120) ∫(9 + 3y²)dy
= (1/120) (18 + 2³)
= 26/120
= 13/60
