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Chrissy C
Chrissy C asked in Science & MathematicsMathematics · 6 years ago

CALCULUS DERIVATIVE HELP! y=arcsin(costheta)?

I simplified the equation down to -sintheta/sq rt 1-costheta then down to -sintheta/sintheta then down to -1. Now, I know my derivative is correct, but my instructor said it could be considered a piecewise function. Can someone explain where I went wrong in simplifying?

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  • ?
    Lv 7
    6 years ago
    Favorite Answer

    y = arc sin(cos theta)

    sin y = cos theta

    Now take the derivative wrt theta

    cos y dy/dtheta = - sin theta

    This gives

    d y/ d theta = - sin theta/cosy = -sin theta /sqrt(1-sin^2 y)=- sin theta/(sqrt( 1- cos^2 theta)

  • Anonymous
    6 years ago

    ss

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