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What is the largest decimal value that can be represented as an 8-bit unsigned integer?
Update:
i thought it was 511 bc 511 = 1+2+4+8+16+32+64+128+2^8...
1 Answer
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- MichaelLv 75 years ago
Well,
1111 1111_base 2 = 2^8 - 1 = 255_base 10
you proposal :
i thought it was 511 bc 511 = 1+2+4+8+16+32+64+1282^8
==> you are confusing with the amount of numbers,
... not the greatest
255 <--- answer
et voilà, mademoiselle !! ;-)
hope it' ll help !!
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