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Algebra 2 homework help!! Which values should be given to a,b, and c so that the system shown has (-1,-2,-3) as its only solution?
System:
X+2y–3z=A
-X – y+z=B
2x+3y–2z=C
Plesse include the steps to solve this, it's for a grade and work must be shown.
**Please
2 Answers
- ?Lv 74 years ago
Given solution:
(-1, -2, -3)
x + 2y – 3z = A
-x – y + z = B
2x + 3y – 2z = C
Values to be given:
(A, B, C) = (4, 0, -2)
- ?Lv 75 years ago
Plug in the values (-1, -2, -3) for (x, y, z)
x + 2y – 3z = A
-1 + 2(-2) - 3(-3) = A
-1 - 4 + 9 = A
4 = A
A = 4 <–––––
---------------------
-x – y + z = B
- (-1) - (-2 ) + (-3) = B
1 + 2 - 3 = B
0 = B
B = 0 <––––
---------------------
2x + 3y – 2z = C
2(-1) + 3(-2) - 2(-3) = C
-2 - 6 + 6 = C
-2 = C
C = -2 <––––
