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Can you help me with a trig question? (sin a/sin b)=2, a+b=90, find a (the angles are in degrees). Thanks!?

5 Answers

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  • 4 years ago

    As given, a + b = 90°, b = 90° - a

    ==> sin(b) = sin(90 - a) = cos(a)

    So, sin(a)/sin(b) = sin(a)/cos(a) = tan(a) = 2

    So a = tan⁻¹(2) = 63.43°

  • sin(a) / sin(b) = 2

    sin(a) = 2 * sin(b)

    a + b = 90

    a = 90 - b

    sin(a) = sin(90 - b)

    sin(a) = sin(90)cos(b) - sin(b)cos(90)

    sin(a) = 1 * cos(b) - sin(b) * 0

    sin(a) = cos(b)

    sin(a) = 2 * sin(b)

    cos(b) = 2 * sin(b)

    cot(b) = 2

    tan(b) = 1/2

    b = arctan(1/2)

    a = 90 - arctan(1/2)

    Make sure your calculator is in degree mode

  • 4 years ago

    I get a = atan( 2) = 63.43495 degrees, plus any whole multiple of 180 degrees.

  • cidyah
    Lv 7
    4 years ago

    sin a = 2 sin b

    a+b = 90

    b= 90-a

    sin a = 2 sin (90-a)

    sin a = 2 ( sin(90) cos(a) - cos(90) sin(a))

    sin a = 2 (cos(a) -0)

    sin a = 2 cos a

    sin a - 2 cos a = 0

    divide both sides by cos a

    tan a - 2 = 0

    tan a = 2

    a = tan^-1(2) = 1.10715 radians

    = (1.10715)(180/pi) = 63.44 degrees

    b=90-a

    b= 90-63.44 = 26.56 degrees

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  • 4 years ago

    If a + b = 90, then sin(b) = cos(a), so the first equation implies that

    sin(a) = 2*cos(a) =>

    sin^2(a) = 4*cos^2(a) =>

    sin^2(a) = 4*(1 - sin^2(a)) =>

    5*sin^2(a) = 4 =>

    sin^2(a) = 4/5 =>

    sin(a) = 2/sqrt(5) =>

    a = 63.43 degrees, b = 26.57 degrees;

    and there are some other answers involving related angles, or by switching a with b.

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