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I need some help with Statistics/Probability. Help!?
The population parameters below describe the full-time equivalent number of students (FTES) each year at Lake Tahoe Community College from 1976–1977 through 2004–2005.
• μ = 1000 FTES
• median = 1,014 FTES
• σ = 474 FTES
• first quartile = 528.5 FTES
• third quartile = 1,447.5 FTES
• n = 29 years
A sample of 11 years is taken. About how many are expected to have a FTES of 1014 or above? Explain how you determined your answer.
***NOTE: I don't quite get what I am supposed to do...so far I guess calculated the IQR which is 919 FTES. After that, I am lost.
1 Answer
- cidyahLv 73 years ago
(Not sure of my answer)
μ = 1000
σ = 474
standardize x to z = (x - μ) / σ
P(x > 1014) = P( z > (1014-1000) / 474)
= P(z > 0.0295) = 0.488
(From Normal probability table)
11*0.488 = 5.368
About 5 out of 11 are expected to have a FTES of 1014 or above
Assume normal distribution as the mean and the median are somewhat the same.
Find the probability of a given FTES exceeding 1014
