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A brass plug to be placed in ring of Fe.At 20 ∘C,diameter of plug=8.725 cm. that of the inside of the ring =8.715 cm .?
Update:
hey must be brought to what common temp to fit?
Update 2:
They must be brought to what common temp to fit?
2 Answers
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- oubaasLv 72 years ago
8.715*(1+12*10^-6*(20+ΔT)) = 8.725*(1+18*10^-6*(20+ΔT))
8.715+0.00209+0.000105ΔT= 8.725+0.00314+0.000157ΔT
8.715+0.00209-(8.725+0.00314) = 0.000052*ΔT
ΔT = (8.715+0.00209-(8.725+0.00314))/0,000052 = -213°C
T = 20+ΔT = 20-213 = -193°C
- Anonymous2 years ago
No
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