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Math Identities qsts, will award best answer, pls help?
prove the following:
1. (cosθ/ secθ -1) + (cosθ/ secθ +1) = 2cot^2*θ
2. (sinθ + tanθ) / (cosθ +1) = tanθ
3. (1-cos 2θ) / (sin 2θ) = tanθ
Answering even one question would be helpful, thanks so much!
1 Answer
- Wayne DeguManLv 711 months agoFavorite Answer
1) [(cosθ/(secθ - 1)] + [(cosθ/(secθ + 1)] = 2cot²θ
Considering the left side we have:
cosθ/(secθ - 1) + cosθ/(secθ + 1)
so, [cosθ(secθ + 1) + cosθ(secθ - 1)]/(secθ - 1)(secθ + 1)
=> [2cosθsecθ]/(sec²θ - 1)
Now, sec²θ => tan²θ + 1 so,
[2cosθsecθ]/tan²θ
Also, secθ => 1/cosθ so,
[2cosθ/cosθ]/tan²θ
i.e. 2/tan²θ
=> 2cot²θ...RHS
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