Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Can you find the mass of the exoplanet?
Given...
That a spaceship orbits in the equatorial plane of an exoplanet , and an observer on the spaceship measures the following:
The exoplanet's angular equatorial diameter at periapsis
Dₑ₀ = 16.3060482°
The exoplanet's angular equatorial diameter at apoapsis
Dₑ₁ = 12.0634564°
The exoplanet's angular polar diameter at periapsis
Dᵨ₀ = 16.2567986°
The exoplanet's angular polar diameter at apoapsis
Dᵨ₁ = 12.0271323°
The spaceship's sidereal orbital period around the exoplanet
P = 108000 sec
The spaceship's altitude above the exoplanet's surface at periapsis
h₀ = 52568218 meters
Find...
The exoplanet's mass
The exoplanet's average density
The semimajor axis of the spaceship's orbit
The eccentricity of the spaceship's orbit
2 Answers
- 6 months ago
The orbit's eccentricity
e = [sin(½Dₑ₀)/sin(½Dₑ₁)−1] / [sin(½Dₑ₀)/sin(½Dₑ₁)+1]
e = 0.1488
The planet's equatorial radius
Rₑ = 2h₀ / {(1−e)[csc(½Dₑ₀)+csc(½Dₑ₁)] − 2}
Rₑ = 8687064 meters
The orbit's periapsis radius
r₀ = Rₑ+h₀
r₀ = 61255282 meters
The orbit's semimajor axis
a = r₀/(1−e)
a = 71963442 meters
The planet's average radius
R = Rₑ ∛{sin(½Dᵨ₀)/sin(½Dₑ₀)}
R = 8678368 meters
The planet's geometric volume
V = (4π/3)R³
V = 2.737807e+21 m³
The planet's average density
ρ = 3πa³/(GP²R³)
ρ = 6903.026 kg m⁻³
The planet's mass
M = ρV
M = 1.889915e+25 kg
The orbit's apoapsis radius
r₁ = a(1+e)
r₁ = 82671602 meters
Orbital speed at periapsis, relative to the planet's center
v₀ = √[GM(2/r₀−1/a)]
v₀ = 4863.786 m/s
Orbital speed at apoapsis, relative to the planet's center
v₁ = √[GM(2/r₁−1/a)]
v₁ = 3603.808 m/s
The planet's polar radius
Rᵨ = R³/Rₑ²
Rᵨ = 8661002 meters
The planet's oblateness
f = 1 − Rᵨ/Rₑ
f = 0.003
The planet's surface gravity at the equator, assuming that it isn't rotating
g = GM/Rₑ²
g = 16.71483 m/s²
The planet's escape speed from the surface at the equator
v = √(2GM/Rₑ)
v = 17041.292 m/s
- Anonymous7 months ago
can you just give a 5 star best answer please