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Physics Power?

A 1000 kg sports car accelerates from rest to 25.0 m/s in 7.50 s. What is the average power output of the automobile engine? Please show work. I do not know how to solve this.

2 Answers

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  • 2 months ago
    Favorite Answer

    a = Δv/Δt = 25/7.5 = 3.333 m/s²

    d = ½at² = ½3.333•7.5² = 93.75 m

    F = ma = 1000 x 3.333 = 3333 N

    Work = Fd = 3333 N x 93.75 m = 312460 J

    power = work/time = 312460 J/7.5 s = 41700 J/s or watts

    or

    a = V/t

    d = ½at² = ½(v/t)t² = ½vt

    F = ma = mv/t

    W = Fd = (mv/t)(½vt) = ½mv²

    P = W/t = ½mv²/t = ½1000•25²/7.5 = 41700 w

  • 2 months ago

    The gain of kinetic energy is (1/2)(1000 kg)(25.0 m/s)^2

    = 312.5 kJ.

    As this was achieved in 7.5 seconds,

    the average power was (312.5 kJ)/(7.5 s) = 41.7 kW.

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