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Limit of Rational Function...3?

Find the limit of (5x)/(100 - x) as x tends to 100 from the left side.

The side condition given: 0 <= x < 100

To create a table, I must select values of x slightly less than 100. I did that and ended up with negative infinity as the answer. The textbook answer is positive infinity. How is this done?

2 Answers

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  • Favorite Answer

    Change the parameters

    u = 100 - x

    x = 100 - u

    5x / (100 - x) =>

    5 * (100 - u) / u =>

    5 * (100/u - u/u) =>

    5 * (100/u  -  1) =>

    500/u  -  5

    0 </= x < 100

    0 </= 100 - u < 100

    -100 </= -u < 0

    0 < u </= 100

    Notice that as u goes to 0, 500/u tends to positive infinity.

    I don't know how you got negative infinity, to be honest, since 100 - x will always be positive when x is between 0 and 100 and 5 * x will be positive as well.

    x = 99.99

    5 * 99.99 / (100 - 99.99) =>

    5 * 99.99 / 0.01 =>

    5 * 9999 =>

    49995

    x = 99.999

    5 * 99.999 / (100 - 99.999) =>

    5 * 99.999 / 0.001 =>

    5 * 99999 =>

    499995

    And so on.

  • 4 days ago

    You'd have negative if you went over 100.  I'll do this with 99.999:

    (5x) / (100 - x)

    (5 * 99.999) / (100 - 99.999)

    499.995 / 0.001

    499995

    That's a large number (huge compared to the 100), the closer I get to 100 and higher it will get, so it's positive infinity from the left (when x < 100).

    And as you found out, it's negative infinity from the right (when x > 100)

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