(2X^3Y) ^-1(2XY^-2) ^2?
The answer I came up with is 2XY^-5. Is that correct? If not, could you explain how to get the correct answer? Thanks!
The answer I came up with is 2XY^-5. Is that correct? If not, could you explain how to get the correct answer? Thanks!
Jim
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(2X^3Y) ^-1(2XY^-2) ^2
(2X^3Y) ^(2XY^-2) ^2 = +1
(2X^3Y) ^(2XY^-2) = v2+1
(2X^3Y) (2XY^-2)/v = v2+1/v
(2XY^-2)/v (2X^3Y)= v2+1/v /(2X^3Y)
(2Y^-2)/v (2X^Y)= v2+1/v /(2X^3Y) xy
(^-2)(^y)= v2+1/v /(2X^3Y) xy(2y2x)v
(^) (^)= beer