A problem of cubes?

If the cubes are allowed to overlap, I think we have

11 x 17 x 23 = 4301 cubes of size 1

10 x 16 x 22 = 3520 cubes of size 2

9 x 15 x 21 = 2835 cubes of size 3

8 x 14 x 20 = 2240 cubes of size 4

7 x 13 x 19 = 1729 cubes of size 5

6 x 12 x 18 = 1296 cubes of size 6

5 x 11 x 17 = 935 cubes of size 7

4 x 10 x 16 = 640 cubes of size 8

3 x 9 x 15 = 405 cubes of size 9

2 x 8 x 14 = 224 cubes of size 10

1 x 7 x 13 = 91 cubes of size 11

So the total number of cubes is 18216

The number of n x n x n cubes in an a x b x c rectangular structure (where a, b, c, and n are integers) is (a - n + 1)(b - n + 1)(c - n + 1)

Therefore, the number of cubes contained is:

11 x 17 x 23 + 10 x 16 x 22 + 9 x 15 x 21 + 8 x 14 x 20 + 7 x 13 x 19 + 6 x 12 x 18 + 5 x 11 x 17 + 4 x 10 x 16 + 3 x 9 x 15 + 2 x 8 x 14 + 1 x 7 x 13 + 0 x 6 x 12

= 18216 cubes

^_^

number of cubes in the structure are 11*17*23 = 4301

First of all you get volume

Volume V of cuboid (rectangle structure) = L*B*H

V = 11*17*23

V = 4301 unit cube

thus 4301 cubes is the answer

infinite

ur bra is coming out