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Tiff
Lv 5
Tiff asked in Science & MathematicsMathematics · 1 decade ago

How would you put this in an equation and simplify it?

1. Key in the first three digits of your phone number (NOT the Area code)

2. Multiply by 80

3. Add 1

4. Multiply by 250

5. Add the last 4 digits of your phone number

6. Add the last 4 digits of your phone number again.

7. Subtract 250

8. Divide number by 2

Assuming your phone number was 234-5678

9 Answers

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  • Anonymous
    1 decade ago
    Favorite Answer

    Let x = prefix and y = last 4

    (250(80x+1)+2y-250)/2

    (20000x + 250 + 2y - 250) / 2 carry out first order of multiplication

    (20000x + 2y) / 2 combine like terms

    10000x + y complete indicated division

  • 1 decade ago

    1. Equation = 234

    2. Equation = 234 * 80 = 18720

    3. Equation = (234 * 80) + 1 = 18721

    4. Equation = ((234 * 80) + 1) * 250 = 4680250

    5. Equation = ((234 * 80) + 1) * 250 + 5678 =4685928

    6. Equation = ((234 * 80) + 1) * 250 + 5678 + 5678 = 4691606

    7. Equation = ((234 * 80) + 1) * 250 + 5678 + 5678 - 250 = 4691356

    8. Equation = (((234 * 80) + 1) * 250 + 5678 + 5678 - 250)/2 = 2345678

    2345678

  • 1 decade ago

    ((234*80+1)*250+5678+5678-250)/2

    or ((234*80+1)*250+2*5678-250)/2

    (instead of adding the last 4 twice, just multiply by 2

    this simplifies to your original phone number, no matter what that number is.

  • ?
    Lv 5
    1 decade ago

    Let a = first three digits and b = last 4 digits, then

    answer = ((a*80+1)*250+2*b -250)/2 = 10000a +b.

    So, your telephone number 234-5678 becomes 2345678.

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  • 1 decade ago

    z = (250 * (80x + 1) + 2y - 250) / 2

    z = (20000x + 250 + 2y - 250) / 2

    z = (20000x + 2y) / 2

    z = 10000x + y

    x is the first 3 digits, y is the last 4.

    Therefore, the solution just shifts the first 3 digits over 4 places and adds the last 4 digits, to get the phone number.

  • 1 decade ago

    (((X)(80)+1)(250) + Y + Y -250)/2

    (20000X+250+2Y-250)/2

    (10000)(X)+Y

    if X = 234 and Y = 5678

    2340000+5678=2345678

  • 1 decade ago

    ((250 * (80 * (100a + 10b + c) + 1)) + (2000d + 200e + 20f + 2g) - 250) / 2

    ((250 * (8000a + 800b + 80c + 1)) + (2000d + 200e + 20f + 2g) - 250) / 2

    (2000000a + 200000b + 20000c + 250) + (2000d + 200e + 20f + 2g) - 250) / 2

    (2000000a + 200000b + 20000c + 2000d + 200e + 20f + 2g)/ 2

    1000000a + 100000b + 10000c + 1000d + 100e + 10f + g

    The answer is your phone number.

  • Anonymous
    5 years ago

    This helps because the bottom part of the equation 9y^2 - 4 into (3y-2) (3y+2), and therefore you can cancel out the (3y+2) on the top with the (3y+2) on the bottom. Your final answer will then be: (2y-3) / (3y-2). Hope this helps!!

  • 1 decade ago

    [{[[(237)(80) +1](250)] +5678(2)}-250]/2=2,345,678

    234-5678

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