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Can some one help me with Alegbra homework?
1. Twice the sum of 16 and a number is the same as that number increased by 36 1/2. Find The number.
2. Amy is twice as old as jenny. five years ago, Amy was three times as old as jenny. Find jenny's age.
3.The quotient of a number and 4 is increased by 7. The result is -31. What is the number?
thanks so much!!
3 Answers
- greenwhiteLv 41 decade agoFavorite Answer
1) 2(16+x) = x + 36 1/2
2) Let Jenny's age be x.
2x-5 = 3(x-5)
3) x/4 + 7 = -31
- 1 decade ago
1. 2(16+n) = n + 32 1/2. Distribute.
32+2n=n+32.5. Combine the N's.
32+n=32.5. Subtract 32.
n=.5 or 1/2.
Then check the work.
2. a=Jenny's age.
2a-5 = 3(a-5). Distribute.
2a-5 = 3a- 15. Combine the a's.
-5=a-15. Add 15.
10=a.
Check the work.
3. (n/4) + 7 = -31. Subtract 7.
(n/4) = -38. Multiply by 4.
n= -152.
Check the work.
Hope this helped!
- 1 decade ago
2(16+x)=x+36.5
2j=3j-5
x/4+7=-31
those are your equations
32+2x=x+36.5
-32
2x=x+4.5
-x
x=4.5
2j=3j-5
subtract 3j
-j=-5
divide by -1
j=5
x/4+7=-31
-7
x/4=-38
times by 4
x=-152
HEY ON INDIESKY SHE put 32.5 NOT 36.5
