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eastcoastrockerdude
eastcoastrockerdude asked in Science & MathematicsMathematics · 1 decade ago

dimension question (geometry)?

i have a triangle that measures 10 feet long across the base, and 5 feet high. because the sides are angled, they will effectively take away length the higher you go up them. what is the length at 27" inches high?

Update:

54 feet is longer than 10 feet..?

2 Answers

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  • Anonymous
    1 decade ago
    Favorite Answer

    draw the diagram as i m explaining below..

    so, the given triangle is ABC. where BC=10ft and perpendicular from A to BC is AD=5ft

    now, draw PQ parallel to BC at height 2.25ft from BC.

    drop perpendicular from A to intersect PQ at M and BC at N.

    v see that triangles ABC and APQ are similar by AA.

    so, PQ/BC=AM/AN

    ie,PQ/10=(5-2.25)/5 (as 27 inches=2.25ft)

    ie, PQ=5.5ft

  • Pranil
    Lv 7
    1 decade ago

    Base1/Base2 = height1/height2

    10/Base2 = 5/27

    Base2 = 27×10/5 = 54 feet

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