can somone tell me the weight of water in a cylinder,?

Solution :

Solving first the volume of a cylinder ;

V = pi * r^2 * h

where :

V = volume of cylinder = ?

pi = constant = 3.1416

r = radius = 1/2 of diameter = 9 feet

h = depth or height = 4 feet

V = (3.1416)*(9^2)*(4)

V = 1,017.88 cubic feet

density of water = 1,000 kg/cu.m

or 62.4 lbs/cu.ft

1 cu.m. = 35.31 cu. ft.

Wt. of water = 1,017.88 cu.ft x 62.4 lbs/cu.ft

= 63,515.71 lbs (answer)

or

= 1,017.88 cu.ft. x 1 cu.m./35.31 cu.ft. x 1,000 kg/cu.m.

= 28,826.96 kgs

= 28.827 tons (answer)

The weight would be volume x density

volume = Pi R*2 H = 3.14 x 9*2 x 4 = 1017 cu ft

water's density = 62 lb/cu ft

62 x 1017 = 63,000 lb

Hope that helps...

V = Pi * R^2 * D

It is simpler in metric units to calculate.... 1 cc = 1 gram, or one cubic meter = one metric tonne 1000kgs.

R = 9 ft = (9*12*2.54)

9 * 12 * 2.54 = 274.32 cm

D = 4 ft = (4*12*2.54)

4 * 12 * 2.54 = 121.92 cm

V = Pi * R^2 * D

3.14 * (274.32^2) * 121.92 = 28,808,427 cc

Since 1 cc of water weights 1 gram, we can also say

28,808,427 grams

or 28.8 Metric Tonnes.

or convert back to lbs if you really want to...

28 808 427 / 456 = 63,176.375 lbs

28 808 427 / (456 * 2 000) = 31.5881875 Tons (normal US measure)

Great