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froghead
Lv 5
froghead asked in Science & MathematicsMathematics · 1 decade ago

What do you get for an answer and how did you get it Calculus?

OK the first question is y'=(3-x^2)(x^3-x+2)

(a) Find Y' (a) by applying the product rule (I got this right -5x^4+12x^2-4x-3) the next part I don't get

(b) By multiplying the factors to produce the sum of simpler terms to differentiate

y'=? (don't know if you can see but those are y primes)

Update:

could you explain your process with your answer. I tried everything from foiling them, to the chain rule and it said my answer was wrong. I guess I am not understanding what they are asking

1 Answer

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  • JOS J
    Lv 7
    1 decade ago

    y[x] = 6 x - (3 x^2)/2 - (2 x^3)/3 + x^4 - x^6/6 + C[1]

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