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Quadratic formula help? No B and a question in general?

I have a homework problem that has 49z(to the second power) = 1. I know you can bring the 1 over to C by subtracting it to both sides, but how do you solve B? Do you just do it without B?

Also, I'm doing something wrong with the formula completely, apparently.

For example I have for one problem:

x(to the second) + 5x - 6 = 0, so I wrote the formula as;

-5 +/- (square root of) 5 (2nd) - 4*(1)*(-6) over 2.

I then got 5 (2nd) = 25, -4*1*-6 = 24.

Then adding those together; 49

49/2 = 24.5

Square root of 24.5 = 4.949

then:

-5 + 4.949 = -.051, and -5 - 4.949 = -9.949.

...according to my book, that isn't the answer >.<

Help please with either of these?

3 Answers

Relevance
  • 9 years ago
    Favorite Answer

    For the first question, you do not need b.

    49z^2 -1 = 0

    The easiest way to solve this is to use factoring.

    49z^2 -1 = 0

    (7z + 1)(7z -1) = 0

    z = 1/7 or -1/7

    The quadratic formula is:

    -b +- √(b^2 - 4ac) / 2 = 0

    Therefore,

    = -5 +- √(25 +24) /2

    = -5 +- √(49) /2

    = -5 +- 7 /2

    One is -5 + 7 /2 which is

    2/2 = 1

    The other is -5 - 7 / 2 which is

    -12/2 = -6

    Therefore the answer is x = 1 or -6

    Source(s): If you want to know how to use factoring instead of the quadratic formula for questions such as the first one, check this link: http://www.purplemath.com/modules/solvquad.htm
  • Nancy
    Lv 6
    9 years ago

    For 49z^2 = 1 --> 49z^2 - 1 = 0 then a = 49, b = 0, and c = -1

    z = (-0 +- sqrt(0 - 4(49)(-1)))/2(49) = +- sqrt(196)/98 = +- 14/98 = +- 1/7

    The second equation: x^2 + 5x - 6 = 0 --> a = 1, b = 5, and c = -6

    x = (-5 +- sqrt(25 - 4(1)(-6)))/2 = (-5 +- sqrt(49))/2 = (-5 +- 7)/2 --> (-5 + 7)/2 = 1 or (-5 - 7)/2 = -6

  • 9 years ago

    for the first one if there is not B term that means B = 0

    so 4z^2 -1 = 0

    z = (-(0) +- sqrt(0^2 - 4(4)(-1))/2(4)

    z = sqrt(16)/8

    z = 4/8

    z = 1/2

    for the second one

    x^2 +5x -6 = 0

    x = (-(5)+-sqrt((5)^2-4(1)(-6))/2(1)

    x = (-5 +- sqrt(25 + 24) )/2

    x = (-5 +- sqrt(49))/2

    x = (-5 +- 7 ) /2

    x = 1 OR x = -6

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