Factoring: I am lost... How do you factor 4x^3-7x^2-15x?
Arolena2010-04-06T23:56:01Z
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4x^3-7x^2-15x Pull out x x(4x^2-7x-15) Set equal to zero x(4x^2-7x-15)=0 x=0 4x^2-7x-15=0 x=0 (4x+5)(x-3)=0 x=0 x=-5/4 x=3 Totally Factored =x(4x+5)(x-3)